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Nucleotide synthesis
Posted by: jamie2k04 (IP Hidden, New member, 1)
Date: May 9, 2006 11:00AM

Hey,

Does anyone know why, during the synthesis of nucleotides (namely using Ribose as the base pentose) that the phosphodiester bridge is formed on the 3rd Carbon group (hydroxyl OH-) and not the 2nd Carbon (hydroxyl OH-) group?

Even though, it appears to me that both groups on the pentose (Ribose) are free to react?

Is it anything to do with the charge distribution along the molecule and the tetrahedal shape of the organic molecule?

It's really bugging me lol

Thanks



Edited 1 times. Last edit at 05/09/06 11:01AM by jamie2k04.

 

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